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authorBorislav Petkov <bp@suse.de>2022-03-08 18:05:43 +0100
committerBorislav Petkov <bp@suse.de>2022-04-11 12:04:11 +0200
commit713c4ff8859c3db4dc8dbf5eec33434b9a3fb76b (patch)
tree0246f68ed5652c8573d9053482da45014181331f /drivers/edac
parent0d24a49e88b563608f9a0393cc99bf117e9fba5b (diff)
EDAC/mc: Get rid of edac_align_ptr()
Get rid of it now that it is unused. Signed-off-by: Borislav Petkov <bp@suse.de> Link: https://lore.kernel.org/r/20220310095254.1510-6-bp@alien8.de
Diffstat (limited to 'drivers/edac')
-rw-r--r--drivers/edac/edac_mc.c55
-rw-r--r--drivers/edac/edac_module.h2
2 files changed, 0 insertions, 57 deletions
diff --git a/drivers/edac/edac_mc.c b/drivers/edac/edac_mc.c
index c7c11b113ace..387b6851c975 100644
--- a/drivers/edac/edac_mc.c
+++ b/drivers/edac/edac_mc.c
@@ -170,61 +170,6 @@ const char * const edac_mem_types[] = {
};
EXPORT_SYMBOL_GPL(edac_mem_types);
-/**
- * edac_align_ptr - Prepares the pointer offsets for a single-shot allocation
- * @p: pointer to a pointer with the memory offset to be used. At
- * return, this will be incremented to point to the next offset
- * @size: Size of the data structure to be reserved
- * @n_elems: Number of elements that should be reserved
- *
- * If 'size' is a constant, the compiler will optimize this whole function
- * down to either a no-op or the addition of a constant to the value of '*p'.
- *
- * The 'p' pointer is absolutely needed to keep the proper advancing
- * further in memory to the proper offsets when allocating the struct along
- * with its embedded structs, as edac_device_alloc_ctl_info() does it
- * above, for example.
- *
- * At return, the pointer 'p' will be incremented to be used on a next call
- * to this function.
- */
-void *edac_align_ptr(void **p, unsigned int size, int n_elems)
-{
- unsigned int align, r;
- void *ptr = *p;
-
- *p += size * n_elems;
-
- /*
- * 'p' can possibly be an unaligned item X such that sizeof(X) is
- * 'size'. Adjust 'p' so that its alignment is at least as
- * stringent as what the compiler would provide for X and return
- * the aligned result.
- * Here we assume that the alignment of a "long long" is the most
- * stringent alignment that the compiler will ever provide by default.
- * As far as I know, this is a reasonable assumption.
- */
- if (size > sizeof(long))
- align = sizeof(long long);
- else if (size > sizeof(int))
- align = sizeof(long);
- else if (size > sizeof(short))
- align = sizeof(int);
- else if (size > sizeof(char))
- align = sizeof(short);
- else
- return ptr;
-
- r = (unsigned long)ptr % align;
-
- if (r == 0)
- return ptr;
-
- *p += align - r;
-
- return (void *)(((unsigned long)ptr) + align - r);
-}
-
static void _edac_mc_free(struct mem_ctl_info *mci)
{
put_device(&mci->dev);
diff --git a/drivers/edac/edac_module.h b/drivers/edac/edac_module.h
index aa1f91688eb8..96f6de0c8ff6 100644
--- a/drivers/edac/edac_module.h
+++ b/drivers/edac/edac_module.h
@@ -59,8 +59,6 @@ extern void edac_device_reset_delay_period(struct edac_device_ctl_info
*edac_dev, unsigned long value);
extern void edac_mc_reset_delay_period(unsigned long value);
-extern void *edac_align_ptr(void **p, unsigned size, int n_elems);
-
/*
* EDAC debugfs functions
*/